Question

What change occurs to the gravitational force of attraction between two bodies when the

distance between them is made half (1/2) by keeping masses constant?​

Answer 1

when the radius is halved, F becomes 4 times

Step-by-step explanation:

The formula is given by

`F = (Gm1m2)/(r^2)`

When r is halved:

`F = (Gm1m2)/((1/2r)^2)`

=>
`F = (Gm1m2)/(1/4 r^2)`

=>
`F = 4((Gm1m2)/(r^2) )`

This means when the radius is halved, F becomes 4 times