Question

Triangle ABC has vertices A(4,5), B(8,9), and C(6,7). What are the vertices of triangle A′B′C′ if triangle ABC is translated according to the algebraic description (x, y) → (x + 3, y – 2)?

Answer 1

A'(7,3), B'(11,7) and C'(9,5).

Explanation:

The vertices of given triangle are A(4,5), B(8,9), and C(6,7).

Given rule of translation is

`(x,y)\rightarrow (x+3,y-2)`

We need to find the vertices of triangle A'B'C'.

Now,

`A(4,5)\rightarrow A'(4+3,5-2)=A'(7,3)`

`B(8,9)\rightarrow B'(8+3,9-2)=B'(11,7)`

`C(6,7)\rightarrow C'(6+3,7-2)=C'(9,5)`

Therefore, the vertices of triangle A'B'C' are A'(7,3), B'(11,7) and C'(9,5).