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Triangle ABC has vertices A(4,5), B(8,9), and C(6,7). What are the vertices of triangle A′B′C′ if triangle ABC is translated according to the algebraic description (x, y) → (x + 3, y – 2)?

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Answer:

A'(7,3), B'(11,7) and C'(9,5).

Explanation:

The vertices of given triangle are A(4,5), B(8,9), and C(6,7).

Given rule of translation is


(x,y)\rightarrow (x+3,y-2)

We need to find the vertices of triangle A'B'C'.

Now,


A(4,5)\rightarrow A'(4+3,5-2)=A'(7,3)


B(8,9)\rightarrow B'(8+3,9-2)=B'(11,7)


C(6,7)\rightarrow C'(6+3,7-2)=C'(9,5)

Therefore, the vertices of triangle A'B'C' are A'(7,3), B'(11,7) and C'(9,5).

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