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What is the center of the circle given by the equation below?
(x + 4)2 + (y - 4)2 = 1
A. (-4,-4)
B.
(4,-4)
C.
(-4,4)
D.
(5,5)
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User Dubbaluga
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2 Answers

6 votes
option C is correct.
User Qohelet
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Answer:

Option C is correct

Explanation:

A typical circle has equation in form of (x - a)^2 + (y - b)^2 = r^2, in which, (a, b) is center and r is radius.

A circle has the equation as below:

(x + 4)^2 + (y - 4)^2 = 1

<=>(x - (-4))^2 + (y - 4)^2 = 1^2

=> The center of this circle is (a, b) = (-4, 4) and the radius r = 1

=> Option C is correct

Hope this helps!

User Farhadi
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