Question

A 50-cm-long spring is suspended from the ceiling. A 410 g mass is connected to the end and held at rest with the spring unstretched. The mass is released and falls, stretching the spring by 16 cm before coming to rest at its lowest point. It then continues to oscillate vertically. Part A What is the spring constant

Answer 1

25.125 N/m

Step-by-step explanation:

extension on the spring e = 16 cm 0.16 m

mass of hung mass m = 410 g = 0.41 kg

equation for the relationship between force and extension is given by

F = ke

where k is the spring constant

F = force = mg

where m is the hung mass,

and g is acceleration due to gravity = 9.81 m/s^2

imputing value, we have

0.41 x 9.81 = k x 0.16 = 0.16k

4.02 = 0.16k

spring constant k = 4.02/0.16 = 25.125 N/m