Answer : The original concentration of the acid solution is 0.869 M
Explanation :
To calculate the concentration of acid, we use the equation given by neutralization reaction:
![n_1M_1V_1=n_2M_2V_2](https://img.qammunity.org/2021/formulas/chemistry/high-school/zq7o0n49g763sff611gn3rub3npkieiezm.png)
where,
are the n-factor, molarity and volume of acid which is
![H_2SO_4](https://img.qammunity.org/2021/formulas/chemistry/high-school/9jhwefvmn4c2eywglm6c7c6bcy2rpmgwur.png)
are the n-factor, molarity and volume of base which is NaOH.
We are given:
![n_1=2\\M_1=?\\V_1=23.24mL\\n_2=1\\M_2=0.7200M\\V_2=56.10mL](https://img.qammunity.org/2021/formulas/chemistry/college/kt14l6wlab7tfmgpgbs1n8tpdrlvdvqalx.png)
Putting values in above equation, we get:
![2* M_1* 23.24=1* 0.7200* 56.10\\\\M_1=0.869M](https://img.qammunity.org/2021/formulas/chemistry/college/7k8imzrx5pk2zq2steyhu2m4dvx7wfv89l.png)
Therefore, the original concentration of the acid solution is 0.869 M