Question

Fifteen percent of the pigment in paint color A is black. Sixty percent of the pigment in paint color B is black. An unknown amount of paint color B is mixed with 40 ml of paint color A, resulting in a paint that contains 25% black pigment.

Which equation can be used to solve for x, the total amount of paint in the mixture of the two colors?

0.15(40) + 0.6x = 0.25(40 + x)
0.15(40) + 0.6(x – 40) = 0.25(x)
0.15(40) + 0.6x = 0.25(40 – x)
0.15(40) + 0.6(x + 40) = 0.25(x)

Answer 1

Fifteen percent of the pigment in paint color A is black. Sixty percent of the pigment in paint color B is black. An unknown amount of paint color B is mixed with 40 ml of paint color A, resulting in a paint that contains 25% black pigment.

Which equation can be used to solve for x, the total amount of paint in the mixture of the two colors?

0.15(40) + 0.6x = 0.25(40 + x)

0.15(40) + 0.6(x – 40) = 0.25(x)

0.15(40) + 0.6x = 0.25(40 – x)

0.15(40) + 0.6(x + 40) = 0.25(x)

Step-by-step explanation: answer (B) on ED

Answer 2

Answer: 0.15(40) + 0.6(x – 40) = 0.25(x)

Explanation:

Hi, to answer this question we have to write an equation with the information given:

Fifteen percent of the pigment in paint color A is black

15% = 15/100 = 0.15 (decimal form)

0.15 A

Sixty percent of the pigment in paint color B is black

0.6 B

An unknown amount of paint color B is mixed with 40 ml of paint color A,

SO:

0.15 (0.40)

0.6 (x-0.40)

x = total amount of paint in the mixture of the two colors

The result is a paint that contains 25% (0.25 in decimal form)black pigment (x)

0.15(40) + 0.6(x – 40) = 0.25(x)

Feel free to ask for more if needed or if you did not understand something.