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35 votes
35 votes
Solve the following inequality
4x+15≥x+6

User Flybywire
by
3.3k points

2 Answers

20 votes
20 votes

Answer:

x ≥ -3

Explanation:

To determine the solution to the inequality, we need to isolate the variable and its coefficient on one side of the equation. Furthermore, isolate the variable by dividing the coefficient by both sides of the equation. The inequality obtained after doing these steps is the solution to the inequality.

Given inequality:

  • 4x + 15 ≥ x + 6

As said above, let's isolate "x" and it's coefficient on one side of the equation. This can be done by subtracting "x + 15" to both sides of the equation.

  • ⇒ 4x + 15 - (x + 15) ≥ x + 6 - (x + 15)
  • ⇒ 4x + 15 - x - 15 ≥ x + 6 - x - 15
  • ⇒ 3x ≥ -9

As said above, let's further isolate "x" by dividing the coefficient of "x" to both sides of the equation.

  • ⇒ 3x/3 ≥ -9/3
  • x ≥ -3

Therefore, the solution is x ≥ -3.

User Franz Deschler
by
2.7k points
20 votes
20 votes

Answer:


  • \boxed{\sf{x\geq -3}}

Explanation:

The following inequality can be solved by separating the term x from one side.

4x+15≥x+6

First, subtract by 15 from both sides.

4x+15-15≥x+6-15

Solve.

4x≥x-9

Then, you subtract by x from both sides.

4x-x≥x-9-x

Solve.

3x≥-9

Divide by 3 from both sides.

3x/3≥-9/3

Solve.

Divide the numbers from left to right.

-9/3=-3


\Longrightarrow: \boxed{\sf{x\geq -3}}

  • Therefore, the correct answer is x≥-3.

I hope this helps, let me know if you have any questions.

User Prabah
by
3.1k points