What is the standard form of 7+3i/2-5i

asked Feb 4, 2021 141k views

5 votes

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6 votes

Answer:

-1/29+41/29*i

Explanation:

(7+3i)/(2-5i)=(7+3i)(2+5i)/(2-5i)(2+5i)=(14+35i+6i+15i^2)/(4-25i^2)=

(14+41i-15)/(4+25)=(-1+41i)/29=-1/29+41/29*i

Amir Rahnama answered Feb 10, 2021

5.3k points

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