Question

What is the solution to the equation StartFraction 3 Over m + 3 EndFraction minus StartFraction m Over 3 minus m EndFraction = StartFraction m squared + 9 Over m squared minus 9 EndFraction? m = 3 m = 6 all real numbers no solution

Answer 1

D on Edge2020 (No solution)

Explanation:

Answer 2

No solution.

Explanation:

Given fraction is:

`(3)/(m+3) -(m)/(3-m) = (m^2+9)/(m^2-9)\\\Rightarrow (3)/(m+3) +(m)/(m-3) = (m^2+9)/(m^2-9)\\\Rightarrow (3* (m-3)+ m(m+3))/((m+3)(m-3)) = (m^2+9)/(m^2-9)\\\Rightarrow (3 m-9+ m^2+3m)/(m^2-9) = (m^2+9)/(m^2-9)\\\Rightarrow (m^2-9+ 6m)/(m^2-9) = (m^2+9)/(m^2-9)\\If\ m^2-9 \\eq 0\ or\ m \\eq 3\\\Rightarrow m^2-9+ 6m = m^2+9\\\Rightarrow 6m = 18\\\Rightarrow m = 3`

Formula used:

`(a+b)(a-b) = a^(2) -b^(2)`

But, the above equation was solved at the condition that:

`m\\eq 3`

So, there is no solution for the given equation.