Answer:
No difference
Step-by-step explanation:
First, let us calculate the probability of a child being affected by an autosomal recessive disease carried by both of her parents. The parents are heterozygous (carriers). Assuming the allele for the disease is a, their genotypes would be Aa.
Crossing Aa and Aa:
Aa x Aa
AA Aa Aa aa
The theoretical probability of a child being affected is 1/4.
From the cross as well, the fraction of affected children from a random generation of a family with four children from the carrier parents is also 1/4.
Hence, there is no difference between the two probabilities.