Answer:
![(-(20)/(7),(4)/(7))](https://img.qammunity.org/2021/formulas/mathematics/high-school/91lu5frkoxmbbmid83j6sp470ib26qqmpw.png)
Explanation:
Given question is incomplete; here is the complete question.
The directed line segment from L to N has endpoints L(-6,2) and N(5,-3) what are the c and y coordinates of point M which partitions the directed line segment into the ratio 2:5 ?
Segment LM has the endpoints L(-6, 2) and M(5, -3).
A point M which has the coordinates (x, y) divides the segment LM in the ratio of m : n.
Then the coordinates of point M will be,
x =
![(mx_2+nx_1)/(m+n)](https://img.qammunity.org/2021/formulas/mathematics/high-school/e5b2zeqsltpammtucu80rhe60617dgalx5.png)
and y =
![(my_2+ny_1)/(m+n)](https://img.qammunity.org/2021/formulas/mathematics/high-school/9qybx09hhcogn1ottfuwdxcj6rfui3ufxt.png)
If the given ratio m:n = 2:5
x =
![(2(5)+5(-6))/(2+5)](https://img.qammunity.org/2021/formulas/mathematics/high-school/9qe3ytvca2ow4bis9chonzgzj7dj5bknnj.png)
=
![(10-30)/(2+5)](https://img.qammunity.org/2021/formulas/mathematics/high-school/5ozevclid5h5c1x3zz4ggxvtai3pjnuw4b.png)
= -
![(20)/(7)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/wdznax1opzma2f5j1dimt7t00y4eirv1va.png)
y =
![(2(-3)+5(2))/(2+5)](https://img.qammunity.org/2021/formulas/mathematics/high-school/s6r3sbcajgkfwk6t5tvm87ts6o67fix37m.png)
=
![(4)/(7)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/91nv0m2w9ppaurpcg3py2sj2zddpttzux1.png)
Therefore, coordinates of point M will be
![(-(20)/(7),(4)/(7))](https://img.qammunity.org/2021/formulas/mathematics/high-school/91lu5frkoxmbbmid83j6sp470ib26qqmpw.png)