Question

Triangle A B C. Angle C is 90 degrees. Hypotenuse A B is 26, adjacent side A C is 24, opposite C B is 10. For the triangle above, find sin A. a. 36° c. 0.9323 b. 50° d. 0.385

Answer 1

Option (D).

Explanation:

In the figure attached,

ΔACB is a right triangle with AC = 24 units, BC = 10 units and AB = 26 units

For angle A,

Adjacent side = AC

Opposite side = BC

Hypotenuse = AB

SinA =
`\frac{\text{Opposite side}}{\text{Hypotenuse}}`

=
`(BC)/(AB)`

=
`(10)/(26)`

SinA = 0.3846

≈ 0.385

Therefore, Option (D) will be the answer.