Question

If 196L of air at 1 atm is compressed to 2600mL,what is the new temperature?​

Answer 1

Around 3.62 degrees kelvin

Step-by-step explanation:

Assuming this is at STP:

The first step is to convert 2600mL to liters. There are 1000 milliliters in a liter, meaning that this is equal to 2.6L.

Now:

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)\\\\\\(196(1))/(273)=(2.6(1))/(T_2) \\\\\\T_2\approx 3.62K`

Hope this helps!