Answer:
The correct answer is option (c) 4950 cipher keys
Step-by-step explanation:
Solution
Given that:
From the given question we have that if there are 100 computers in a LAN, then each computer should have how many keys.
Now,
The number of computers available = 100
The number of keys used in symmetric key cipher for N parties is given as follows:
= N(N-1)/2
= 100 * (100 -1)/2
= 50 * 99
= 4950 cipher keys