Question

The distance between Joshua's home and school is 800 m. Joshua takes 5 min to walk

the first 100 m to a Convenient Store nearby. He would spend 10 min in the store to
complete his purchase. Finally, he takes another 20 min to reach school. What is his
average speed in m/s?

Answer 1

= 0.38 m/s

Explanation:

▪Total distance = 800 m

5 min = 100 m

▪Remaining distance = 800 - 100 = 700 m

20 min = 700 m

▪Total time taken = 20 + 10 + 5 = 35 min

If 1 min = 60 sec

What about 35 min = ?

= 35 x 60

= 2100 sec

▪Average speed = TD ÷ TT

= 800 ÷ 2100

= 0.38 m/s