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5 votes
Algebra applications ​

Algebra applications ​-example-1
User Junji Zhi
by
5.3k points

2 Answers

5 votes

Answer:

X=55°

Y=30°

Explanation:

2y=x+5

Y=1/2x+2.5

3y+30=4x-100

3(0.5x+2.5)+30=4x-100

1.5x+7.5+30=4x-100

4x-1.5x=137.5

2.5x=137.5

X=55°

Y=30°

User Baptx
by
6.3k points
6 votes

Answer:


x = 55\\y = 30\\

Explanation:

Finding x:

4x - 100 + x + 5 = 180 (Angles on a straight line)

5x - 95 = 180

5x = 180 + 95

5x = 275

Dividing both sides by 5

x = 55

Finding y:

2y + 3y +30 = 180 (Angles on a straight line)

5y = 180-30

5y = 150

Dividing both sides by 5

y = 30

User Hajo Kirchhoff
by
5.7k points