Question

Can someone help me with this?

Answer 1

0.25 seconds

Explanation:

First let's expand the function h:

`h = -16(t- 1/4)^2 + 49`

`h = -16(t^2 - t/2 + 1/16) + 49`

`h = -16t^2 + 8t - 1 + 49`

`h = -16t^2 + 8t + 48`

To find when the marshmallow reaches the maximum height, we can use the formula to find the vertex of the quadratic function, and the x-coordinate of the vertex is when we have the maximum height:

`x_(vertex) = -b/2a`

In our equation, b = 8 and a = -16, so:

`t_(vertex) = -8 / (-32) = 0.25\ seconds`