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5 votes
10 ft

8 ft


Find the perimeter of this figure to the
nearest hundredth. Use 3.14

10 ft 8 ft Find the perimeter of this figure to the nearest hundredth. Use 3.14-example-1

2 Answers

1 vote

Answer:56.56

Explanation:

For the perimeter of a rectangle

P = 2 × (a + b)

P = 2 × (8 + 10)

P = 2 × 18

P = 36

For the perimeter of a semicircle

P = (pi × r) + (2 × r)

Diameter = 8

Radius = 8/2

Radius = 4

P = (3.14 × 4) + (2 × 4)

P = 12.56 + 8

P= 20.56

Perimeter of this figure

P = r + c

P = 36 + 20.56

P = 56.56

User Umer Kiani
by
6.7k points
4 votes

Answer:

48.56 ft

Explanation:

==>Given:

A rectangular figure joined with a half circle with the following dimensions:

Length of rectangle (l) = 10ft

Width of rectangle (w) = 8ft

Diameter of the half circle (d) = the width of the rectangle = 8ft

π = 3.14

==>Required:

Perimeter of the figure = perimeter of a rectangle + permimeter of the half circle

==>Solution:

Perimeter of rectangle = 2(l + w)

Perimeter of half circle = ½ of circumference of a circle = ½πd

Perimeter of the figure = 2(10 + 8) + (½*3.14*8)

= 2(18) + (3.14*4)

= 36 + 12.56

Perimeter = 48.56 ft (to the nearest hundredth)

User GalileoMonkey
by
7.0k points
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