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The median of the marks 10, 13, 3x-1, 3x+1, 18, 18 arranged in ascending order is

15. Find the following:
a)
Marks
b)
Mode
c)
Range

The median of the marks 10, 13, 3x-1, 3x+1, 18, 18 arranged in ascending order is-example-1

1 Answer

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Answer:

a. Marks = 10, 13, 14, 16, 18, 18

b. mode = 18

c. Range = 8

Explanation:

==>Given the following data set arranged in ascending order:

10, 13, 3x-1, 3x+1, 18, 18

Median = 15

==>Required:

a. Marks:

To get each marks, let's find the value of x since we know median to be 15.

10, 13, [3x-1, 3x+1], 18, 18

Our median in this even number of data set would be the average of the 2 middle values which would give us 15.

Thus, we have:

[(3x-1) + (3x+1)] ÷ 2 = 15

[3x-1 + 3x+1] ÷ 2 = 15

[3x+3x-1+1] ÷ 2 = 15

6x/2 = 15

Multiply 2 by both sides

6x = 30

Divide 6 by both sides

x = 5

Now let's plug in the value of x to get out marks:

10, 13, 3(5)-1, 3(5)+1, 18, 18

10, 13, 14, 16, 18, 18

b. Mode is the most appeared data value, which is 18

c. Range is the difference between the highest and lowest value = 18 - 10 = 8

User Md Rahman
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