Answer:
Evaluate f(7)
![f(7) = 240(0.7)^7 = 19.765](https://img.qammunity.org/2021/formulas/mathematics/college/xr7z1a24hclk1agxyk8hv9fsgtmyxc788e.png)
Determine x when f(×)=120
![120 = 240 (0.7)^x](https://img.qammunity.org/2021/formulas/mathematics/college/j41kfbi8e5zy5jp6p35tan7jqrsow9d862.png)
We can derive both sides by 240 and we got:
![0.5 = 0.7^x](https://img.qammunity.org/2021/formulas/mathematics/college/s2r84fpdi3lxhr4q1x1hhgosf3o83yjkd5.png)
Now we can apply natural log on both sides and we got:
![ln(0.5)= x ln(0.7)](https://img.qammunity.org/2021/formulas/mathematics/college/ism5a10zxbf47fv95x799rqtfqhqbez7uw.png)
And if we solve for the value of x we got:
![x =(ln(0.5))/(ln(0.7))= 1.943](https://img.qammunity.org/2021/formulas/mathematics/college/p1daugg5c2safayj5amyhqdpks2gcjq83n.png)
And then the value of x = 1.943
Explanation:
We have the following function given:
![f(x) = 240(0.7)^x](https://img.qammunity.org/2021/formulas/mathematics/college/s1qqq8poufuolleop8czzcridnigw9k6vk.png)
Evaluate f(7)
And we want to find
so we just need to replace x=7 and we got:
![f(7) = 240(0.7)^7 = 19.765](https://img.qammunity.org/2021/formulas/mathematics/college/xr7z1a24hclk1agxyk8hv9fsgtmyxc788e.png)
Determine x when f(×)=120
And for the second part we want to find a value of x who satisfy that the function would be equal to 120 and we can set up this:
![120 = 240 (0.7)^x](https://img.qammunity.org/2021/formulas/mathematics/college/j41kfbi8e5zy5jp6p35tan7jqrsow9d862.png)
We can derive both sides by 240 and we got:
![0.5 = 0.7^x](https://img.qammunity.org/2021/formulas/mathematics/college/s2r84fpdi3lxhr4q1x1hhgosf3o83yjkd5.png)
Now we can apply natural log on both sides and we got:
![ln(0.5)= x ln(0.7)](https://img.qammunity.org/2021/formulas/mathematics/college/ism5a10zxbf47fv95x799rqtfqhqbez7uw.png)
And if we solve for the value of x we got:
![x =(ln(0.5))/(ln(0.7))= 1.943](https://img.qammunity.org/2021/formulas/mathematics/college/p1daugg5c2safayj5amyhqdpks2gcjq83n.png)
And then the value of x = 1.943