Question

What is the equation, in point-slope form, for a line that goes through(8,

4) and has a slope of - 5/6?
oy-4--5 (x+8)
Oy-4--5 (2-8)
O y+4= -5 (0-8)
O y+4= -= (2+8)

Answer 1

`\boxed{y-4=-(5)/(6)(x-8)}`

Explanation:

Point slope form is:
`y-y_1=m(x-x_1)`

`(x_1,y_1) - Coordinate\\ m- Slope`

We are given the slope of
`-(5)/(6)` and the point of (8,4).

Replace 'm' with -5/6, 'x1' with 8, and 'y1' with 4.

`y-y_1=m(x-x_1)\rightarrow \boxed{y-4=-(5)/(6)(x-8)}`

I do not see any options that match this, but the boxed equation should the correct answer.