Answer:
![(1)/(30240)](https://img.qammunity.org/2021/formulas/mathematics/high-school/crgpb5n9xsfz21xx466dohson391ng7vk0.png)
Explanation:
Given
ID Card of 5 digits
Possibly Digits = {0,1...,9}
Required
Probability that a card has exact number 94213
First, we have o determine the total possible number of ID card numbers
Let the card number be represented by ABCDE
Given that repetition of digits is not allowed;
A can be any of 10 digits
B can any of the remaining 9 digits
C can be any of the remaining 8 digits
D can be any of the remaining 7 digits
E can be any of the remaining 6 digits
Total number of cards = 10 * 9 *8 * 7 * 6
Total = 30240
Provided that the card number is generated at random; each card number has the same probability of
![(1)/(30240)](https://img.qammunity.org/2021/formulas/mathematics/high-school/crgpb5n9xsfz21xx466dohson391ng7vk0.png)
Hence, the probability of having 94213 is
![(1)/(30240)](https://img.qammunity.org/2021/formulas/mathematics/high-school/crgpb5n9xsfz21xx466dohson391ng7vk0.png)