x = - b \binom{ + }{ - } \sqrt{b {}^(2) } - 4ac / 2a x {}^(2) - 4x + 3 = 0 \: please \: answer \: for me mathematics

asked Oct 7, 2021 152k views

2 votes

$x = - b \binom{ + }{ - } \sqrt{b {}^(2) } - 4ac / 2a$

$x {}^(2) - 4x + 3 = 0 \: please \: answer \: for me$
mathematics

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5 votes

Answer:

x1= 3

x2 = 1

Step-by-step explanation:

I hope it helps

$x = - b \binom{ + }{ - } \sqrt{b {}^(2) } - 4ac / 2a x {}^(2) - 4x + 3 = 0 \: please-example-1$

$x = - b \binom{ + }{ - } \sqrt{b {}^(2) } - 4ac / 2a x {}^(2) - 4x + 3 = 0 \: please-example-2$

Melvyn answered Oct 12, 2021

7.1k points

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