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Write the standard form of a circle with a center at C(-4, -6) and passes through the point (-1, -2).

1 Answer

4 votes

Answer:

(x+4)^2+(y+6)^2 = 25

Explanation:

The radius squared is equal to the distance between the center and the point

3^2 + 4^2 = 25

We can shift the center like this

(x+4)^2+(y+6)^2 = 25

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