Question

Point P is located at (−2, 7), and point R is located at (1, 0). Find the y value for the point Q that is located two thirds the distance from point P to point R. 4.9 4.7 2.5 2.3

Answer 1

Answer: I Believe its 2.3

Explanation:

P is located at (-2,7)

R is located at (1,0)

Look at the y coordinates

P(-2,7) R(1,0)

7 to 0= distance of 7

multiply 2/3 by 7 = 4.7 (it was originally 4.666666665 but i couldnt find the answer with just 4.6 so i rounded it to 4.7)

Now plug in the info we know:

.y axis = 7 - 4.7 = 2.3

Hope this helped! Im taking the test and ill be back if this is wrong

Answer 2

5.1

Explanation:

Before we calculate the y value for the point Q that is located two thirds the distance from point P to point R, we need to get the distance of point p from point R using the formula for calculatingf the distance between two points

D = √(x2-x1)²+(y2-y1)²

Given P(−2, 7), and R(1, 0)

RP = √(1-(-2))²+(0-7)²

RP = √3²+(-7)²

RP = √9+49

RP =√58

To get the y value for point Q that is located two thirds the distance from point P to point R, this will give

PQ = y = 2/3 of √58

= 5.1