The volume, in liters, of 538 g of CO2

asked Sep 17, 2021 152k views

5 votes

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3 votes

Answer:

12.23moles in 1000cm3

Step-by-step explanation:

Mass=moles×molermass

538=44xY

Y=538÷44

Y=12.23moles in 1000cm3

Chuckd answered Sep 22, 2021

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