Final answer:
The question involves calculating specific probabilities for a binomial distribution corresponding to the number of owned dogs spayed or neutered out of 48 selected. Exact calculations were not provided due to absence of corresponding information in the question but would typically be carried out using a binomial probability formula or computation tool.
Step-by-step explanation:
The question requires finding probabilities for a binomial distribution, with a population proportion of 0.67 for dogs being spayed or neutered, and 48 trials representing the 48 randomly selected owned dogs. Unfortunately, the provided information (Solution 2.7, Solution 2.8, etc.) does not directly apply to this binomial probability question, so we will solve it using the binomial probability formula instead.
The binomial probability formula is P(X = k) = (n choose k) * p^k * (1-p)^(n-k), where 'n' is the number of trials, 'k' is the number of successes, and 'p' is the probability of success on a single trial. For cumulative probabilities, such as "at most" or "at least", we sum individual probabilities from the binomial distribution.
Step-by-step explanations
Exactly 29 spayed or neutered: Use the binomial probability formula with n=48, k=29, and p=0.67 to find the probability.
At most 33 spayed or neutered: Sum the probabilities P(X = k) for k=0 up to k=33.
At least 30 spayed or neutered: Calculate 1 - the probability of at most 29 being spayed or neutered.
Between 28 and 33 spayed or neutered: Sum the probabilities for k=28 up to k=33.
Calculations will involve using either a binomial probability table, a calculator with a binomial probability function, or software that can compute these values.