Answer:
v = 10
the average velocity of the object over the interval of time [1, 5 ] is 10 units per unit time
Explanation:
Given;
function s(t) represents the position of an object at time t moving along a line.
s(1) = 62 at t1 = 1
s(5) = 102 at t5 = 5
Velocity v = distance/time
Average velocity v over time t is;
v = ∆s/∆t
v = [s(5) - s(1)]/[t5 - t1]
Substituting the given values;
v = (102 - 62)/(5 - 1)
v = 10
the average velocity of the object over the interval of time [1, 5 ] is 10 units per unit time