Answer:
£1,330.46
Explanation:
Using the compound interest formula
![A = P(1+(r)/(n) )^(nt)](https://img.qammunity.org/2021/formulas/mathematics/high-school/c6vt0jd6h3vz456fgf60jxfke9qav5nepb.png)
A = amount compounded after n years
P = principal (amount invested)
r = rate (in %)
t = time (in years)
n = time used to compound the money
Given P = £1200., r = 3.5%, t = 3years, n = 1 year(compounded annually)
![A = 1200(1+0.035)^(3)\\ A = 1200(1.035)^(3)\\ A = 1200* 1.108717875\\A = 1,330.46](https://img.qammunity.org/2021/formulas/mathematics/high-school/9vjve9gyj6ian4qglg14xgutunhp4t9drz.png)
Value of Charlie's investment after 3 years is £1,330.46