Question

Please help! For the function f(x) = 2x^6 + 3x^4 - 4x^3 + (1/x) - sin(2x) find the first four derivatives.

Answer 1

Explanation:

First derivative

`12x^5+12x^3 -x^(-2)-2cos (2x)`

Second derivative

`60x^4+36x^2+2x^(-3)+4sin(2x)`

Third derivative

`240x^3+72x-6x^(-4)+8cos(2x)`

Fourth derivative

`720x^2+72+24x^(-5)-16sin(2x)`