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The largest z-score available in most tables is 2.99, which corresponds to a probability of 99.86%. A fair coin is

tossed 200 times.
a) What number of heads observedžwould correspond to a z-score of 2.99? [2]

User Fresca
by
5.8k points

1 Answer

6 votes

Answer:

The number of heads observed is 121.14 heads

Explanation:

The formula for the z-score of a proportion is given as follows;


z=\frac{\hat{p}-p}{\sqrt{(pq)/(n)}}

Where:


{\hat{p} = Sample proportion

p = Population success proportion = 0.5

q = 1 - p = 1 - 0.5 = 0.5

n = Number in of observation = 200

z = 2.99

Hence, we have;


z=\frac{\hat{p}-0.5}{\sqrt{(0.5 * 0.5)/(200)}} = 2.99

Therefore;


{\hat{p}-0.5}{} = 2.99 * \sqrt{(0.5 * 0.5)/(200)} = 2.99 *(√(2) )/(40)


{\hat{p} = 0.6057


Whereby \ \hat p = (Number \ of \ heads)/(Number \ of \ observation) = (Number \ of \ heads)/(200) = 0.6057

∴ The number of heads observed = 200 × 0.6057 = 121.14 heads.

User Heberti Almeida
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