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Consider the quadratic equation y^2-y=6. what is the error with the solution below?

1 Answer

4 votes

Answer:

y=-2 or y=3

Explanation:

Y^2-y-6=0

y^2-3y+2y-6=0

y(y-3)+2(y-3)=0

(y+2)(y-3)=0

y=-2 or y=3

hope it helps

User RDelorier
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