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It has been suggested that rotating cylinders about 12.5 mi long and 3.99 mi in diameter be placed in space and used as colonies. What angular speed must such a cylinder have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth

User Keysl
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1 Answer

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Answer:

The correct answer to the following question will be "0.0562 rad/s".

Step-by-step explanation:


r =(3.9)/(2)* 1609.34


=3138.213\ m

As we know,


\omega^2 \ r=g

On putting the values, we get


\omega^2* 3138.213=9.8


\omega = \sqrt{(9.8)/(3138.213)}


\omega = 0.0562 \ rad /s

User Eric Baker
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