Answer:
0.1833
Explanation:
Given:
% of people with fibromyalgia = 2%
Probability of having a restless leg syndrome for people with fibromyalgia = 0.33
Probability of having a restless leg syndrome for people without fibromyalgia = 0.03
Take F as event of having fibromyalgia
Take R as event of having restless leg
Required:
Find the probability that a person with restless leg syndrome has fibromyalgia.
To find the probability that a person with restless leg syndrome has fibromyalgia, we have: P(F/R)
![P(F/R) = (P(F n R))/(P(R))](https://img.qammunity.org/2021/formulas/mathematics/college/wkf54o8qbxquh4sohp2yhil18qud3vplav.png)
![P(F/R) =(P(R/F) * P(F))/(P(R/F) * P(F) + P(R/F^c) * P(F^c))](https://img.qammunity.org/2021/formulas/mathematics/college/el74ivnvlo4zr5lgblzuvt6ml2jazn9hw3.png)
Where,
P(R/F) = 0.33
P(F) = 2% = 0.02
P(R/F') = 0.03
P(F') = 1 - 0.02 = 0.98
Therefore,
![P(F/R) = (0.33 * 0.02)/(0.33*0.02 + 0.03*0.98)](https://img.qammunity.org/2021/formulas/mathematics/college/ealg08iu3pnvhcytgw7uikgvvwoz1hjipo.png)
= 0.1833
Probability a person with restless leg syndrome has fibromyalgia = 0.1833
Tree diagram is attached