Question

In a system using the relocatable dynamic partitions scheme, given the following situation (and using decimal form): Job Q is loaded into memory starting at memory location 42K. a. Calculate the exact starting address for Job Q in bytes. b. If the memory block has 3K in fragmentation, calculate the size of the memory block. c. Is the resulting fragmentation internal or external

Answer 1

a) The exact starting address for Job Q is 43008 bytes

b) The size of the memory block is 46080 bytes

c) Resulting fragmentation is external

Step-by-step explanation:

a) Job Q starting address

42 k ⇒ 42 × 1024 = 43008.

b) memory block has 3 k in fragmentation ∴ the size of the memory block is calculated as 3 k ⇒ 3 × 1024 = 3072.

The fact that it is a block means that we have end address = 3072 + 43008 = 46080.

c) External Fragmentation: It will come in a system that uses the relocatable dynamic partitions scheme.