Answer: d) similar, SAS similarity, ΔDGH
Explanation:
DG ≡ GC ⇒ G is the midpoint of DC
DH ≡ HB ⇒ H is the midpoint of DB
Therefore, HB is the midsegment of ΔDCB.
By the Midsegment Theorem, HB || BC
By Corresponding Angles Theorem, ∠DGH ≡ ∠DCB
ΔDCB ≅ ΔDGH by Side-Angle-Side Similarity Theorem