Question

Pls help i need answer

Answer 1

14m

Explanation:

Step1:

Consider the first right angled triangle using Pythagoras Theorem:

(hyponenus)^2 = (opposite)^2 + (adjacent)^2

20^2 = 12^2 + A^2

A^2 = 400 - 144 = 256

A = Square root of 256 = 16m

Step2:

CONSIDER THE SECOND RIGHT_ ANGLED TRIANGLE:

adjacent=24-16=8m

opposite=12m

Hypotenus=?

(hypotenus)^2 = (opposite)^2 + (adjacent)^2

H^2=12^2+8^2=

144+64

H^2=208

H=square root of 208=14.42m

To the nearest meter=14m

Hope it helps.

Answer 2

b. 14 m

Explanation:

base of left side triangle

• √20²-12²= √256= 16 m

base of right side triangle

• 24-16= 8 m

missing length

• √12²+8²= √208= 14.42 m

Option b. 14 m is closest one