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2 votes
2 votes
A 40kg cart gains a KE of 200J. How fast does it go?

User Chris Sprague
by
2.8k points

1 Answer

19 votes
19 votes

Answer:

3.16 m/s

Step-by-step explanation:

Use the formula


k = \frac{m {v}^(2) }{2} \\ v = \sqrt{ (2k)/(m) } \\ v = \sqrt{ (2(200))/(40) } \\ v = 3.16 (m)/(s)

User Polkas
by
2.7k points