Question

a gas has a volume of 2.00 at 323k and 3.00 ATM What would be the new volume if the temperature is changed to 273 K in the pressure is changed to 1ATM

Answer 1

Apply combine gas law

`\\ \rm\Rrightarrow (P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

`\\ \rm\Rrightarrow (3(2))/(323)=\dfrav{V_2}{273}`

`\\ \rm\Rrightarrow 6(273)=323V_2`

`\\ \rm\Rrightarrow 1638=323V_2`

`\\ \rm\Rrightarrow V_2=5.07L`

Answer 2

`V_2 = 5.07L`

Step-by-step explanation:

`(P_1 V_1)/(T_1) = (P_2 V_2)/(T_2)\\V_2 = (P_1 V_1 T_2)/(T_1 P_2) = (3.00atm \cdot 2.00L \cdot 273K)/(323K \cdot 1.00atm) = 5.07L`