Question

Calculate the root mean square velocity, in m/s, of carbon dioxide molecules at 100.0

Answer 1

459.8m/s

Step-by-step explanation:

T=Temperature in Kelvin

M=molar mass in kg/mol

Molar mass of CO2,

mm=44.01g/mol

=0.04401kg/mol

T =100.0C

= (100.0 +273) K

=373K

So,

vrms= sqrt(3×R×T/M)

vrms=sqrt(3×8.314×373.0/0.04401)

=459.8m/s