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A spinner is shown at the fight

A spinner is shown at the fight-example-1

1 Answer

3 votes

Answer: .3, .1, .5, .6, .5

Explanation:


\large \frac{\text{quantity of shaded spaces}}{\text{Total spaces}}=(3)/(10)=\large\boxed{.3}\\\\\\\frac{\text{quantity of 5s}}{\text{Total spaces}}=(1)/(10)=\large\boxed{.1}\\\\\\\frac{\text{quantity of even numbers}}{\text{Total spaces}}=(5)/(10)=\large\boxed{.5}\\\\\\\frac{\text{Total - white spaces}}{\text{Total spaces}}=(10-4)/(10)=\large\boxed{.6}\\\\\\\frac{\text{white spaces + number of 7s}}{\text{Total spaces}}=(4+1)/(10)=\large\boxed{.5}\\

User George Fisher
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