Question

For many purposes we can treat methane (CH) as an ideal gas at temperatures above its boiling point of - 161. °C. Suppose the temperature of a sample of methane gas is raised from 100.0 °C to 119.0 °C, and at the same time the pressure is decreased by 15.0%. increase Does the volume of the sample increase, decrease, or stay the same? decrease x 6 ? stays the same If you said the volume increases or decreases, calculate the percentage change in the volume. Round your answer to the nearest percent. 1%

Answer 1

Step-by-step explanation:

T₁ = 100 + 273 = 373K

T₂ = 273 + 119 = 392 K

V₁ = initial volume

V₂ = Final volume

P₁ = P₁

P₂ = .85P₁

Using gas law equation

`(P_1* V_1)/(T_1) =(P_2* V_2)/(T_2)`

`= (P_1* V_1)/(373) =(.85P_1* V_2)/(392)`

V₂ = 1.236 V₁

% increase in volume

= V₂-V₁ / V₁ x 100

= (1.236 V₁ - V₁ / V₁)x 100

= .236 x 100

= 23.6 % .