Answer:
21,600
Explanation:
If in the coding system being used there are 6 vowels (A, E, I , O, U and Y)
Number of Consonants =26-6 =20
- First entry must be a consonant, therefore the first entry can be chosen in 20 ways.
- The second entry must be an integer 1 through 9, therefore the second entry can be chosen in 9 ways.
- The third entry must be one of the six vowels, therefore the third entry can be chosen in 6 ways.
- The last entry must be a consonant, therefore the last entry can be chosen in 20 ways.
Therefore:
Number of different possible ciphers =20*9*6*20
=21600