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Preform the operation indicated 3x^2(2x^2-5x+1)

1 Answer

2 votes

Answer:

6x^4 -15x^3 + 3x^2

Explanation:

What we want to do here is to multiply what is outside the bracket with what is inside

That would be;

3x^2(2x^2 -5x + 1)

= 3x^2(2x^2) -5x(3x^2) + 1(3x^2)

Opening the brackets, we have;

6x^4 -15x^3 + 3x^2

User Thomas Hupkens
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