Question

Paul rolls a fair dice 174 times. How many times would Paul expect to roll a number greater than 2?

Answer 1

116 times

Explanation:

A fair dice has 6 faces: 1, 2, 3, 4, 5, 6

The probability of rolling a number greater than 2( face of 3, 4, 5, 6 - 4 elements in total) is:

P = number of selected elements/total number of elements

P = 4/6

P = 2/3

=> Paul rolls a fair dice 174 times, Paul will expect the number of times that a number greater than 2 is rolled:

N = 174 x (2/3) = 116

Hope this helps!