Question

Pls help with this maths question... feels like I'm missing something easy ;/​

Answer 1

10.34 cm.

Explanation:

First we need to calculate the angle between the hour and minute hand

We see that there are 5 * 5-minute intervals between the 2 hands and the clock has 12 * 5-minute intervals, so:

This is 5/12 * 360 = 150 degrees,

So we apply the Cosine Rule to the triangle:

x^2 = 4.5^2 + 6.2^2 - 2*4.5*6.2cos150

= 107.014

x = √107.14 = 10.34.

Answer 2

Missing length is 10.3cm to 1.d.p

The clock is a circle divided into 12

360/12=30 degrees for each part

1) 7 to 8

2) 8 to 9

3) 9 to 10

4) 10 to 11

5) 11 to 12

5 parts

30 x 5 = 150 degrees

We've got an angle between 2 lengths - cosine rule comes to mind for me.

a = root 6.2^2 + 4.5^2 - 2x6.2 4.5 x cos 150

= 10.34476764

length is 10.3cm to 1.d.p

(the others are to 1.d.p too)

Hope this helps!