Answer:
The amount of rains that can be stored in the two silos combined is 5242.53 ft³
Step-by-step explanation:
The parameters given are;
Diameter, D, of the silos = 15 feet
Height, h₁, of the larger silo = 18 feet 10 inches = 18.83 feet
Height, h₂, of the shorter silo = 10 feet 10 inches = 10.83 feet
The volume, V, of the cylindrical shape is given by the formula;
Volume = Area of base × Height
![Area \, of \, the \, base = \pi * (D^(2))/(4)](https://img.qammunity.org/2021/formulas/engineering/middle-school/ogh2xxsp4zcq6eg2io6jj8ccuam0rm9s2d.png)
![\therefore Volume = \pi * (D^(2))/(4)* h](https://img.qammunity.org/2021/formulas/engineering/middle-school/nz2c9m5bocvz7gmsq0etp9teyu6yr77pou.png)
Therefore, for the larger silo, we have;
![Volume, V_1 = \pi * (D^(2))/(4)* h_1](https://img.qammunity.org/2021/formulas/engineering/middle-school/oqsiso7ybefxy5q3zcpwquo730ytmtj8ey.png)
![V_1 = \pi * (15^(2))/(4)* 18.83 = 3328.12 \ ft^3](https://img.qammunity.org/2021/formulas/engineering/middle-school/8x0s1n695689jtzdcjqe905huqv2jplqf6.png)
for the shorter silo, we have;
![Volume, V_2 = \pi * (D^(2))/(4)* h_2](https://img.qammunity.org/2021/formulas/engineering/middle-school/93dxfbvz5uycx8uzjixn8v36hvewekc6ze.png)
![V_2 = \pi * (15^(2))/(4)* 10.83 = 1914.41\ ft^3](https://img.qammunity.org/2021/formulas/engineering/middle-school/9sdsxijo5g42jue4z9fzyjxva9pu8k6bkn.png)
The amount of rains that can be stored in the two silos combined = 3328.12 ft² + 1914.41 ft² = 5242.53 ft².