Question

The area of rectangle is ( 30x²y + 20xy ) cm² and its breadth is 10xy cm .Find its length.

Subtract the quotient when 20x⁴y² is divided by 5x³y from the product of 2x and 3y.
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Answer 1

Explanation:

1) The area of rectangle is ( 30x²y + 20xy ) cm² and its breadth is 10xy cm .Find its length....

= Solution ,

Length ( L ) = ?

breadth ( b ) = 10xy cm

area ( a ) = ( 30x² + 20xy )

Now ,

area ( a ) = l × b

or, ( 30x²y + 20xy ) = L × 10xy cm

`or,\frac{30 {xy + 20xy}^(2) }{10xy} = l \\`

`or, \: l = 3 {x}^(2 - 1) + 2cm`

`\boxed{\sf{l = (3x+2)cm}}`

2) Subtract the quotient when 20x⁴y² is divided by 5x³y from the product of 2x and 3y.

= Solution,

`= \frac{20 {x}^(4) {y}^(2) }{5 {x}^(3) y} \\`

`= 4xy`

The product of 3x and 4y = 6xy

= 6x - 4xy

`= \boxed{\sf {2xy}}`

hope it helped !!!!