Question

If Frequency F, velocity v, and density D are considered fundamental units, the dimensional formula for momentum will be :

Answer 1

(Frequency)⁻³(velocity)⁴Density

Step-by-step explanation:

See attachments.

Answer 2

Let's see

Momentum be P

`\\ \rm\Rrightarrow P=[Frequency]^a[velocity]^b[Density]^c`

`\\ \rm\Rrightarrow [P]=[F]^a[v]^b[D]^c`

`\\ \rm\Rrightarrow [M^1L^1T^(-1)]=[T^(-1)]^a[L^1T^(-1)]^b[M^1L^(-3)]^c`

`\\ \rm\Rrightarrow MLT^(-1)=T^(-a)L^bT^(-b)M^cL^(-3c)`

`\\ \rm\Rrightarrow MLT^(-1)=T^(-a-b)L^(b-3c)M^c`

On comaparing

• c=1

So

• b-3c=1
• b-3=1
• b=1+3
• b=4

and

• -a-b=-1
• -a-4=-1
• -a=-1+4=3
• a=-3

So the unit is

• DV⁴/F³