203k views
3 votes
If a random sample of 53 students was asked for the number of semester hours they are taking this semester. The sample standard deviation was found to be s = 4.7 semester hours. How many more students should be included in the sample to be 99% sure that the sample mean x is within 1 semester hour of the population mean  for all students at this college?

User DalyaG
by
7.6k points

1 Answer

4 votes

Answer:

94 more students should be included in the sample.

Explanation:

We have that to find our
\alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:


\alpha = (1-0.99)/(2) = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of
1-\alpha.

So it is z with a pvalue of
1-0.005 = 0.995, so
z = 2.575

Now, find the margin of error M as such


M = z*(\sigma)/(√(n))

In which
\sigma is the standard deviation of the population and n is the size of the sample.

How many students we need to sample to be 99% sure that the sample mean x is within 1 semester hour of the population mean?

We need to survey n students.

n is found when M = 1.

We have that
\sigma = 4.7

So


M = z*(\sigma)/(√(n))


1 = 2.575*(4.7)/(√(n))


√(n) = 2.575*4.7


(√(n))^(2) = (2.575*4.7)^(2)


n = 146.47

Rounding up

147 students need to be surveyed.

How many more students should be included...?

53 have already been surveyed

147 - 53 = 94

94 more students should be included in the sample.

User Vinnydiehl
by
8.7k points

No related questions found